执行如下 C++ 代码,将从小到大依次输出 abs(N) 个整数,并在最后输出 1 。
int N;
cin >> N;
int start_num = 1, end_num = N + 1, i;
if (N < 0)
start_num = N, end_num = 0;
for (i = start_num; i < end_num; i++)
cout << i << " ";
cout << endl << ((i - 1) == abs(N)) << endl;
正确答案：错误（×）