下列代码将十进制转化成八进制，则横线上应填入（ ）。
#include <iostream>
using namespace std;
void decimal2octal(int decimal) {
int oct_number[100];
int i = 0;
while (decimal > 0) {
__________________________ //在此处填入代码
}
for (int j = i - 1; j >= 0; j--) {
cout << oct_number[j];
}
cout << endl;
}
- A. oct_number[i] = decimal % 8; decimal /= 8;
- B. oct_number[i] = decimal / 8; decimal %/= 8;
- C. oct_number[i++] = decimal % 8; decimal /= 8;
- D. oct_number[i++] = decimal / 8; decimal %= 8;
正确答案：C